问题:

七下数学书三元一次方程{1}题X+Y+Z=63X-Y+2Z=12X-Y-3Z=-42题3X-2Y=5Y-5Z=-113Z-4X=23题X+Y-Z=02X-Y+3Z=2X-4Y-2Z+6=04题3X+Y=6X+2Y-Z=55X-3Y+2Z=45题X+Y+Z=-14X-2Y+3Z=5Y-Z=8-2X6题2X+3Y=53Y-4Z=34Z+5X=7注意写出过程

更新时间:2024-04-28 08:06:52

问题描述:

郝贵和回答:

  {1}题X+Y+Z=63X-Y+2Z=12X-Y-3Z=-4

  ①与②相加

  X+Y+Z+3X-Y+2Z=6+12

  4X+3Z=18

  ①与③相加

  X+Y+Z+X-Y-3Z=6-4

  2X-2Z=2

  X-Z=1

  Z=X-1

  代入4X+3Z=18后

  4X+3(X-1)=18

  7X=21

  X=3

  Z==X-1=2

  Y=X-3Z+4=3-3*2+4=1

  2题3X-2Y=5Y-5Z=-113Z-4X=2

  Y-5Z=-11

  Y=5Z-11

  代入3X-2Y=5后

  3X-2(5Z-11)=5

  3X-10Z=-17

  X=10Z/3-17/3

  代入3Z-4X=2

  3Z-4(10Z/3-17/3)=2

  -31z/3=-62/3

  z=2

  x=10Z/3-17/3=1

  y=5Z-11=-1

  3题X+Y-Z=02X-Y+3Z=2X-4Y-2Z+6=0

  X+Y-Z=0

  Z=X+Y

  代入2X-Y+3Z=2

  2X-Y+3(X+Y)=2

  5X+2Y=2

  X=2/5-2Y/5

  代入X-4Y-2Z+6=0

  2/5-2Y/5-4Y-2(2/5-2Y/5+Y)+6=0

  Y=1

  X=0

  Z=1

  4题3X+Y=6X+2Y-Z=55X-3Y+2Z=4

  3X+Y=6

  Y=6-3X

  X+2Y-Z=5

  Z=X+2Y-5=X+2(6-3X)-5=7-5X

  代入5X-3Y+2Z=4后

  5X-3(6-3X)+2(7-5X)=4

  X=2

  Y=6-3X=0

  Z=7-5X=-3

  5题X+Y+Z=-14X-2Y+3Z=5Y-Z=8-2X

  Y-Z=8-2X

  Y=Z-2X+8

  代入X+Y+Z=-1

  X+Z-2X+8+Z=-1

  -X+2Z+8=-1

  X=2Z+9

  Y=Z-2X+8=Z-2(2Z+9)+8=-3Z-10

  代入4X-2Y+3Z=5

  4(2Z+7)-2(-3Z-10)+3Z=5

  Z=-3

  Y=-1

  X=3

  6题2X+3Y=53Y-4Z=34Z+5X=7

  2X+3Y=5

  X=5/2-3Y/2

  3Y-4Z=3

  Z=3Y/4-3/4

  代入4Z+5X=7

  4(3Y/4-3/4)+5(5/2-3Y/2)=7

  Y=5/9

  X=5/3

  Z=-1/3

  另:你(潘潘84),应该学会其【方法】

最新更新